在Windows中处理子进程崩溃

Question

我正在Windows命令提示符下运行python脚本。它调用下面的函数，该函数使用LAME将MP3文件转换为wave文件。

def convert_mp3_to_wav(input_filename, output_filename):
    """
    converts the incoming mp3 file to wave file
    """
    if not os.path.exists(input_filename):
        raise AudioProcessingException, "file %s does not exist" % input_filename

    command = ["lame", "--silent", "--decode", input_filename, output_filename]

    process = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
    (stdout, stderr) = process.communicate()

    if process.returncode != 0 or not os.path.exists(output_filename):
        raise AudioProcessingException, stdout

    return output_filename

不幸的是，LAME总是在某些MP3上崩溃（并达到其名称）。出现Windows“您的程序已崩溃”对话框，该对话框冻结了我的脚本。关闭窗口对话框后，将引发AudioProcessingException。无需告诉Windows关闭，我只想脚本引发异常，然后转到下一个MP3。

有没有办法解决？最好通过更改脚本而不是在Unix上运行脚本。

我正在使用Windows 7和Python 2.6

Answer 1

经过更多的谷歌搜索后，我偶然发现了这个 http://www.activestate.com/blog/2007/11/supressing-
windows-error-report-messagebox-subprocess-and-
ctypes

它需要一些修补，但是下面的方法现在不会出现令人讨厌的Windows消息：）注意subprocess.Popen中的creationflags =subprocess_flags

def convert_mp3_to_wav(input_filename, output_filename):

    if sys.platform.startswith("win"):
        # Don't display the Windows GPF dialog if the invoked program dies.
        # See comp.os.ms-windows.programmer.win32
        # How to suppress crash notification dialog?, Jan 14,2004 -
        # Raymond Chen's response [1]

        import ctypes
        SEM_NOGPFAULTERRORBOX = 0x0002 # From MSDN
        ctypes.windll.kernel32.SetErrorMode(SEM_NOGPFAULTERRORBOX);
        subprocess_flags = 0x8000000 #win32con.CREATE_NO_WINDOW?
    else:
        subprocess_flags = 0



    """
    converts the incoming mp3 file to wave file
    """
    if not os.path.exists(input_filename):
        raise AudioProcessingException, "file %s does not exist" % input_filename

    #exec("lame {$tmpname}_o.mp3 -f {$tmpname}.mp3 && lame --decode {$tmpname}.mp3 {$tmpname}.wav");
    command = ["lame", "--silent", "--decode", input_filename, output_filename]

    process = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.PIPE, creationflags=subprocess_flags)
    (stdout, stderr) = process.communicate()

    if process.returncode != 0 or not os.path.exists(output_filename):
        raise AudioProcessingException, stdout

    return output_filename