A. Soft Drinking

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

This winter is so cold in Nvodsk! A group of n friends decided to buy k bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has l milliliters of the drink. Also they bought c limes and cut each of them into d slices. After that they foundp grams of salt.

To make a toast, each friend needs nl milliliters of the drink, a slice of lime and np grams of salt. The friends want to make as many toasts as they can, provided they all drink the same amount. How many toasts can each friend make?

Input

The first and only line contains positive integers n, k, l, c, d, p, nl, np, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space.

Output

Print a single integer — the number of toasts each friend can make.

Sample test(s)

input

3 4 5 10 8 100 3 1

output

2

input

5 100 10 1 19 90 4 3

output

3

input

10 1000 1000 25 23 1 50 1

output

0

Note

A comment to the first sample:

Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is min(6, 80, 100) / 3 = 2.

解题说明：此题就是输入参数较多，理清参数含义即可

#include <iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#define min(a,b) (a<b)?(a):(b) 
using namespace std;

int main()
{

	int n, k, l, c, d, p, nl, np;
	int temp1,temp2,temp3,ans1,ans;
	scanf("%d %d %d %d %d %d %d %d",&n,&k,&l,&c,&d,&p,&nl,&np);
	temp1=(k*l)/nl;
	temp2=c*d;
	temp3=p/np;
	ans1=min(temp1,temp2);
	ans=min(ans1,temp3);
	printf("%d\n",ans/n);
    return 0;
}