ACTF新生赛2020 crypto-classic1

哇，这里有压缩包的密码哦，于是我低下了头，看向了我的双手，试图从中找到某些规律
xdfv ujko98 edft54 xdfv pok,.; wsdr43

键盘码，得到的密码为circle

密文为：SRLU{LZPL_S_UASHKXUPD_NXYTFTJT}

SRLU未加密前应为ACTF，编写脚本如下：

#破解key
s='ABCDEFGHIJKLMNOPQRSTUVWXYZ' 
s1='ACTF' 
s2='SRLU' 
key =''
for i in range(len(s1)): 
    key+=s[(s.find(s2[i])-s.find(s1[i]))%26] 
print key


#解密
cipher = 'SRLU{LZPL_S_UASHKXUPD_NXYTFTJT}'
key = 'SP'
#decode
flag = ''
for i in range(0,len(cipher)):
	flag += table[(table.find(cipher[i])+26-table.find(key[i%len(key)]))%26]
print flag
#ACTFHWHATKAKCLASSICALKVIGENEREH

'''
cipher = SRLU{LZPL_S_UASHKXUPD_NXYTFTJT}
ACTF{WHAT_A_CLASSICAL_VIGENERE}
'''