题目:给定一个string,找出第一个string里的unique character,如“cisco”的话就应该是i,“cat”的话就是c。
第一种方法是用LinkedHashMap保留数据的顺序,过一遍string,对字符进行计数,然后找到第一个数量为1的字符即可。
第二种方法是用一个HashSet来存已经重复的字符,然后用个arraylist来存仅出现了一次的字符。
第三种方法是用HashMap来存数据以及count,然后再走一遍string,对每个字符检查计数是否为1.
代码:
import java.io.IOException;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.HashSet;
import java.util.LinkedHashMap;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
import java.util.Set;
public class FirstUniqueCharacter {
//方法一
public static char getFirstNonRepeatedChar(String str) {
Map<Character, Integer> counts = new LinkedHashMap<>(str.length());
for (char c : str.toCharArray()) {
counts.put(c, counts.containsKey(c) ? counts.get(c) + 1 : 1);
}
for (Entry<Character, Integer> entry : counts.entrySet()) {
if (entry.getValue() == 1) {
return entry.getKey();
}
}
throw new RuntimeException("didn't find any non repeated Character");
}
//方法二
public static char firstNonRepeatingChar(String word) {
Set<Character> repeating = new HashSet<>();
List<Character> nonRepeating = new ArrayList<>();
for (int i = 0; i < word.length(); i++) {
char letter = word.charAt(i);
if (repeating.contains(letter)) {
continue;
}
if (nonRepeating.contains(letter)) {
nonRepeating.remove((Character) letter);
repeating.add(letter);
} else {
nonRepeating.add(letter);
}
}
return nonRepeating.get(0);
}
//方法三
public static char firstNonRepeatedCharacter(String word) {
HashMap<Character, Integer> scoreboard = new HashMap<>();
// build table [char -> count]
for (int i = 0; i < word.length(); i++) {
char c = word.charAt(i);
if (scoreboard.containsKey(c)) {
scoreboard.put(c, scoreboard.get(c) + 1);
} else {
scoreboard.put(c, 1);
}
} // since HashMap doesn't maintain order, going through string again
for (int i = 0; i < word.length(); i++) {
char c = word.charAt(i);
if (scoreboard.get(c) == 1) {
return c;
}
}
throw new RuntimeException("Undefined behaviour");
}
}
Reference:http://javarevisited.blogspot.com/2014/03/3-ways-to-find-first-non-repeated-character-String-programming-problem.html