CodeforcesT
#include <set>
#include <map>
#include <deque>
#include <stack>
#include <vector>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std;
typedef long long LL;
typedef unsigned long long ULL;
#define rep(i,l,r) for (int i=(l); i<=(r); i++)
#define repd(i,r,l) for (int i=(r); i>=(l); i--)
#define rept(i,c) for (typeof((c).begin()) i=(c).begin(); i!=(c).end(); i++)
#define reset(x) { memset(x, -1, sizeof(x)); }
#ifndef ONLINE_JUDGE
#define debug(x) { cerr<<#x<<" = "<<(x)<<endl; }
#define DBG(id) { cerr<<"DEBUG LABLE = "<<(id)<<endl; }
#else
#define debug(x) {}
#define DBG(id) {}
#endif
const int N = (int)1e6 + 10;
const int M = (int)1e9 + 7;
/*------------------------------------------------------------------------*/
int n, a[N];
int mina, maxa;
void track()
{
int tres = -1;
sort(a + 1, a + n + 1);
rep(i, 1, n)
{
}
cout << tres << endl;
}
int main()
{
#ifndef ONLINE_JUDGE
freopen("C:\\Users\\Administrator\\Desktop\\IDE\\in.txt","r",stdin);
#endif
cin >> n;
rep(i, 1, n)
{
cin >> a[i];
}
track();
return 0;
}
读题读样例。
PS:求滚动区间最值 神器
//单调递增队列1 子区间动态更新
const int maxn=100;
int que[maxm*10+5], idx[maxm*10+5], head = 1, tail = 0;
void queini(){
head = 1, tail = 0, que[0] = 0;// 单调减 que[0] = 99999999;
}
int quein(int index, int value)
{
while(head <= tail && que[tail] <= value) tail--;
que[++tail] = value;
idx[tail] = index;
return 0;
}
int queout(int index, int distence)//index 索引 distence离索引距离
{
while(idx[head] <= index - distence) head++;
return 0;
}
//单调递增队列2
int num[1000001], que[1000001], first, tail;
void queini(){
first = 1, tail = 0, que[0] = 0;
}
int quein(int index)
{
while(num[que[tail]] >= num[index] && first <= tail) tail--;
que[++tail] = index;
return 0;
}
int queout(int index, int distence)
{
while (que[first] <= index - distence) first++;
return 0;
}
成段 + C, 查询区间和
#include <cstdio>
#include <algorithm>
using namespace std;
#define lson l , m , rt << 1
#define rson m + 1 , r , rt << 1 | 1
#define LL long long
const int maxn = 111111;
/* Node Begin */
LL add[maxn<<2];
LL sum[maxn<<2];
/* Node End */
void PushUp(int rt) {
sum[rt] = sum[rt<<1] + sum[rt<<1|1];
}
void PushDown(int rt,int m) {
if (add[rt]) {
add[rt<<1] += add[rt];
add[rt<<1|1] += add[rt];
sum[rt<<1] += add[rt] * (m - (m >> 1));
sum[rt<<1|1] += add[rt] * (m >> 1);
add[rt] = 0;
}
}
void build(int l,int r,int rt) {
add[rt] = 0;
if (l == r) {
scanf("%lld",&sum[rt]);
return ;
}
int m = (l + r) >> 1;
build(lson);
build(rson);
PushUp(rt);
}
void update(int L,int R,int c,int l,int r,int rt) {
if (L <= l && r <= R) {
add[rt] += c;
sum[rt] += (LL)c * (r - l + 1);
return ;
}
PushDown(rt , r - l + 1);
int m = (l + r) >> 1;
if (L <= m) update(L , R , c , lson);
if (m < R) update(L , R , c , rson);
PushUp(rt);
}
LL query(int L,int R,int l,int r,int rt) {
if (L <= l && r <= R) {
return sum[rt];
}
PushDown(rt , r - l + 1);
int m = (l + r) >> 1;
LL ret = 0;
if (L <= m) ret += query(L , R , lson);
if (m < R) ret += query(L , R , rson);
return ret;
}
int main() {
int N , Q;
scanf("%d%d",&N,&Q);
build(1 , N , 1);
while (Q --) {
char op[2];
int a , b , c;
scanf("%s",op);
if (op[0] == 'Q')
{
scanf("%d%d",&a,&b);
printf("%lld\n",query(a , b , 1 , N , 1));
}
else
{
scanf("%d%d%d",&a,&b,&c);
update(a , b , c , 1 , N , 1);
}
}
return 0;
}
离散化 扫描线
sort(X,X+nn);/*unique前必须sort*/
nn = unique(X, X + nn) - X; /*去重并得到总数*/
#include <cstdio>
#include <cstring>
#include <cctype>
#include <algorithm>
using namespace std;
#define lson l , m , rt << 1
#define rson m + 1 , r , rt << 1 | 1
const int maxn = 2222;
int cnt[maxn << 2];
double sum[maxn << 2];
double X[maxn];
struct Seg {
double h , l , r;
int s;
Seg(){}
Seg(double a,double b,double c,int d) : l(a) , r(b) , h(c) , s(d) {}
bool operator < (const Seg &cmp) const {
return h < cmp.h;
}
}ss[maxn];
void PushUp(int rt,int l,int r) {
if (cnt[rt]) sum[rt] = X[r+1] - X[l];
else if (l == r) sum[rt] = 0;
else sum[rt] = sum[rt<<1] + sum[rt<<1|1];
}
void update(int L,int R,int c,int l,int r,int rt) {
if (L <= l && r <= R) {
cnt[rt] += c;
PushUp(rt , l , r);
return ;
}
int m = (l + r) >> 1;
if (L <= m) update(L , R , c , lson);
if (m < R) update(L , R , c , rson);
PushUp(rt , l , r);
}
int Bin(double key,int n,double X[]) {
int l = 0 , r = n - 1;
while (l <= r) {
int m = (l + r) >> 1;
if (X[m] == key) return m;
if (X[m] < key) l = m + 1;
else r = m - 1;
}
return -1;
}
int main() {
int n , cas = 1;
while (~scanf("%d",&n) && n) {
int m = 0;
while (n --) {
double a , b , c , d;
scanf("%lf%lf%lf%lf",&a,&b,&c,&d);
X[m] = a;
ss[m++] = Seg(a , c , b , 1);
X[m] = c;
ss[m++] = Seg(a , c , d , -1);
}
sort(X , X + m);
sort(ss , ss + m);
int k = 1;
for (int i = 1 ; i < m ; i ++) {
if (X[i] != X[i-1]) X[k++] = X[i];
}
memset(cnt , 0 , sizeof(cnt));
memset(sum , 0 , sizeof(sum));
double ret = 0;
for (int i = 0 ; i < m - 1 ; i ++) {
int l = Bin(ss[i].l , k , X);
int r = Bin(ss[i].r , k , X) - 1;
if (l <= r) update(l , r , ss[i].s , 0 , k - 1, 1);
ret += sum[1] * (ss[i+1].h - ss[i].h);
}
printf("Test case #%d\nTotal explored area: %.2lf\n\n",cas++ , ret);
}
return 0;
}
//整数hash
const int maxn = 0xff;
int hash[maxn], count[maxn];
int hashit(int k)
{
int t = k % maxn;
if( t < 0 ) t += maxn;
while( hash[t] != -1 && hash[t] != k ) t = (t + 1) % maxn;
if( hash[t] == -1 ) hash[t] = k, count[t] = 1;
else ++count[t];
}
//字符串hash
const int maxn = 0xff;
int hash[maxn], count[maxn];
void init(){
memset(hash,-1,sizeof(hash));
memset(count,-1,sizeof(count));
}
inline unsigned int BKDRHash(char *str)
{
unsigned int seed = 131; // 31 131 1313 13131 131313 etc..
unsigned int hash = 0;
while (*str)
{
hash = hash * seed + (*str++);
}
return (hash & 0x7FFFFFFF);
}
inline void hashit(char *str)
{
int k,t;
while( *str == '0' ) str++; ///这里有时候不需要去零
k = BKDRHash(str);
t = k % maxn;
while( hash[t] != k && hash[t] != -1 ) t = ( t + 10 ) % maxn;
if( hash[t] == -1 ) hash[t] = k, count[t] = 1;
else ++count[t];
}
(1)二分
/*二分 1-n 闭区间*/
int BinarySearch(int A[],int x)
{
int L = 1, M, R = sizeof(A) / sizeof(int) - 1;
int Bres = -1;
while(L < R){
M = L + (R-L)/2;
if(x < A[M]) R = M;
else L = M+1;
}
return L;
}
(3)dfs
const int SZ = 110;
const int dir[4][2] = {{0,1},{0,-1},{-1,0},{1,0}};
int N, M;
char mat[SZ][SZ], vis[SZ][SZ];
void dfs(int a,int b)
{
if(vis[a][b] | mat[a][b]!='#')return;
vis[a][b] = true;
for(int i = 0;i < 4; ++i)
{
int ti = a + dir[i][0], tj = b + dir[i][1];
if(ti<1 | ti>N | tj<1 | tj>M | vis[ti][tj])continue;
dfs(ti,tj);
}
}
bool vis[N][N];
int bfs( int x, int y)
{
queue<pos> Que;
pos tmp;
reset(vis);
Que.push((pos){x, y});
vis[x][y] = 1;
while(!Que.empty())
{
tmp=Que.front(); Que.pop();
for(int i = 0; i < 4; ++i)
{
int nx, ny;
if(nx | ny) return 1;
if(nx | ny)continue;
q.push((pos){nx, ny}); vis[nx][ny] = 1;
}
}
return 0;
}