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735. Asteroid Collision

金烨华
2023-12-01

We are given an array asteroids of integers representing asteroids in a row.

For each asteroid, the absolute value represents its size, and the sign represents its direction (positive meaning right, negative meaning left).

Find out the state of the asteroids after all collisions. If two asteroids meet, the smaller one will explode. If both are the same size, both will explode.

Example 1:

Input: 
asteroids = [5, 10, -5]
Output: [5, 10]
Explanation: 
The 10 and -5 collide resulting in 10.  The 5 and 10 never collide.

Example 2:

Input: 
asteroids = [8, -8]
Output: []
Explanation: 
The 8 and -8 collide exploding each other.

Example 3:

Input: 
asteroids = [10, 2, -5]
Output: [10]
Explanation: 
The 2 and -5 collide resulting in -5.  The 10 and -5 collide resulting in 10.

Note:

The length of  asteroids will be at most  10000.Each asteroid will be a non-zero integer in the range  [-1000, 1000]..

注意在删除过程中index的变化

class Solution:
    def asteroidCollision(self, asteroids):
        """
        :type asteroids: List[int]
        :rtype: List[int]
        """
        while True:
            t = [i for i in range(len(asteroids)-1) if asteroids[i]>0 and asteroids[i+1]<0]
            if not len(t): break
            shrink = 0
            for i in t:
                i -= shrink
                l, r = asteroids[i], asteroids[i+1]
                asteroids.pop(i)
                shrink += 1
                if l+r>0:  asteroids[i]=l
                elif l+r<0:asteroids[i]=r
                else:  
                    asteroids.pop(i)
                    shrink += 1
        return asteroids
    
s = Solution()
print(s.asteroidCollision([2,-2,2,-2]))
print(s.asteroidCollision([1,-2,1,-2]))
print(s.asteroidCollision([10, 2, -5]))
print(s.asteroidCollision([8,8]))
print(s.asteroidCollision([5, 10, -5]))







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