给你一个500行的文件,已知文件为有序ip段+地址,内如格式如下:
127.1.0.0 127.1.0.255 地址1
127.1.1.0 127.1.1.255 地址2
127.1.2.0 127.1.2.255 地址3
127.1.3.0 127.1.3.255 地址4
127.1.4.0 127.1.4.255 地址5
写一个算法,传入ip地址,获取到地址详情。
以下代码为本人撸出来的,大家给意见吧
package main
import (
"os"
"bufio"
"io"
"fmt"
"strings"
"strconv"
)
type ip struct {
start int
end int
ipStart string
ipEnd string
address string
}
var data []ip
func main() {
data = make([]ip, 0)
data = fGet("./ip.txt")
fmt.Println(searchs("127.1.3.8"))
}
func fGet(file string) []ip {
ipStruct := ip{
start: 0,
end: 0,
ipStart: "",
ipEnd: "",
address: "",
}
ipSlice := []ip{}
fileSource, err := os.Open(file)
if err != nil {
panic("文件不可用")
}
fread := bufio.NewReader(fileSource)
for {
line, _, err := fread.ReadLine()
if err == io.EOF {
break
}
lines := strings.Split(string(line), " ")
ipStruct.start = stringIpToInt(lines[0])
ipStruct.end = stringIpToInt(lines[1])
ipStruct.ipStart = lines[0]
ipStruct.ipEnd = lines[1]
ipStruct.address = lines[2]
ipSlice = append(ipSlice, ipStruct)
}
return ipSlice
}
func stringIpToInt(ipstring string) int {
ipSegs := strings.Split(ipstring, ".")
var ipInt int = 0
var pos uint = 24
for _, ipSeg := range ipSegs {
tempInt, _ := strconv.Atoi(ipSeg)
tempInt = tempInt << pos
ipInt = ipInt | tempInt
pos -= 8
}
return ipInt
}
func searchs(ip string) string {
ipInt := stringIpToInt(ip)
start := 0
end := len(data)-1
index := 0
address := ""
for{
if index == (start + end)/2 {
break
}
index = (start + end)/2
if data[index].start < ipInt && data[index].end > ipInt {
address = data[index].address
break
} else if data[index].start > ipInt {
end = index
continue
} else if data[index].end < ipInt {
start = index
continue
}
}
return address
}