Code Manager 2

授权协议 GPLv2
开发语言 Perl
所属分类 服务器软件、 版本控制系统
软件类型 开源软件
地区 不详
投 递 者 高正初
操作系统 Windows
开源组织
适用人群 未知
 软件概览

Code Manager 2 (CM2) 提供了一个完整的源码控制系统,为开发者提供共享工作目录树的功能。

  • package DogHouse; import java.awt.Color; import java.util.Vector; import robocode.AdvancedRobot; import robocode.HitByBulletEvent; import robocode.HitWallEvent; import robocode.RobotDeathEvent; import

  • Assume you have a method isSubstring which checks if one word is a substring of another. Given two strings, s1 and s2, write code to check if s2 is a rotation of s1 using only one call to isSubstring

  • setting.json {   "powermode.presets": "flames",   // vscode默认启用了根据文件类型自动设置tabsize的选项   "editor.detectIndentation": false,   // 重新设定tabsize   "editor.tabSize": 2,   // #每次保存的时候自动格式化    "editor.formatOn

  • 1  弹出框 <%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">

  • //How would you design a stack which, in addition to push and pop, also has a function //min which returns the minimum element? Push, pop and min should all operate in //O(1) time. #include <math.h>

  • 什么是code code就就是一种语言,一种计算机能读懂的语言。计算机是一个傻逼,他理解不了默认两可的任何东西。比如,你让你老公去买个西瓜,你老公会自己决定去哪里买,买几个,找个搞活动打折的买,总之,你给他钱,他就给你买回来让你吃到爽的西瓜。但是,你想让计算机买一个西瓜?你要告诉他:去门口的鲜丰水果店买,买沙瓤无子西瓜,若旁边的店打折,就去旁边的店买。总之,你不能让计算机做任何决定,你要清楚的告诉

  • //Implement an algorithm to find the nth to last element of a singly linked list. struct LinkNode { LinkNode * next; int value; } LinkNode * findLastN(LinkNode * head, int n) { int i = 1;

  • The smallest organizational unit for which a complete self-contained set of accounts can be drawn up for purposes of external reporting. This includes recording all relevant transactions and generatin

  • #include <iostream> #include <thread> extern "C" { #include "libavutil/avutil.h" #include "libavcodec/avcodec.h " #include "libavformat/avformat.h" } #pragma comment(lib, "avcodec.lib") #pragma comme

  • 题目 一个数组中有三个数字a、b、c只出现一次,其他数字都出现了两次。请找出三个只出现一次的数字。 分析 何在一个数组中找出两个只出现一次的数字。在这道题中,如果我们能够找出一个只出现一次的数字,剩下两个只出现一次的数字就很容易找出来了。 如果我们把数组中所有数字都异或起来,那最终的结果(记为x)就是a、b、c三个数字的异或结果(x=a^b^c)。其他出现了两次的数字在异或运算中相互抵消了。 我们

  • /* ** ** Copyright 2008, The Android Open Source Project ** ** Licensed under the Apache License, Version 2.0 (the "License"); ** you may not use this file except in compliance with the License. ** Yo

  • //Imagine a (literal) stack of plates. If the stack gets too high, it might topple. There- //fore, in real life, we would likely start a new stack when the previous stack exceeds //some threshold. Imp

  • //Implement a function to check if a tree is balanced. For the purposes of this question, //a balanced tree is defined to be a tree such that no two leaf nodes differ in distance //from the root by mo

  • 《Code Interviwer》Part One. Preparation Tips: How to practice coding skills? 1,write codes by hand without complier 2,debug and change them also by hand 3,struggle the process, quality defeat quantity

  • Write code to reverse a C-Style String. (C-String means that “abcd” is represented as five characters, including the null character.) void reverse(char * chr) { char * end = chr; while (*end !=

  • 1.Growth of a Population In a small town the population is p0 = 1000 at the beginning of a year. The population regularly increases by 2 percent per year and moreover 50 new inhabitants per year come

  • Design an algorithm and write code to remove the duplicate characters in a string without using any additional buffer. NOTE: One or two additional variables are fine. An extra copy of the array is not

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