Swift算法实现逐字翻转字符串的方法示例

前言

翻转字符串在字符串算法中算是比较常见的，而且被很多公司用作笔试题。”逐字翻转字符串”是翻转字符串的翻版，也是之前Google的面试题，原题是这样的：

Given an input string, reverse the string word by word.
A word is defined as a sequence of non-space characters.
The input string does not contain leading or trailing spaces and the words are always separated by a single space.
For example,
Given s = "the sky is blue",
return "blue is sky the".
Could you do it in-place without allocating extra space?

简而言之就是：”the sky is blue”—>”blue is sky the”

所以，对于本文，要解决的算法是：

逐字翻转字符串，例如："the sky is blue"—>"blue is sky the"

接下来看下实现思路和代码。

实现思路及代码

既然是字符串翻转的翻版，我们就可以利用之前翻版字符串的思路去解决就可以了，不过这道题要有两次翻转：

第一次翻转，整体翻转：”the sky is blue” -> “eulb si yks eht”

第二次翻转，单词翻转：”eulb si yks eht” -> “blue is sky the”

所以，首先可以实现一个可以翻转局部和全部字符串的算法，传入字符数组、startIndex 和 endIndex ，其中 startIndex 和 endIndex 分别为要翻转的字符串的起始下标和结束下标，也就是要翻转 startIndex 和 endIndex 之间（包含）的字符，代码如下：

func _reverseStr( _ chars:inout [Character], _ startIndex:Int, _ endIndex:Int){
 
 var startIndex = startIndex
 var endIndex = endIndex
 
 if startIndex <= endIndex {
  
  let tempChar = chars[endIndex]
  chars[endIndex] = chars[startIndex]
  chars[startIndex] = tempChar
  
  startIndex += 1
  endIndex -= 1
  
  _reverseStr(&chars,startIndex,endIndex)
  
 }
 
}

之后就可以利用上面的算法去完成前面说的两次翻转：

func reverseWords(_ str:String) -> String{
 
 var chars = [Character](str.characters)
 
 //首先翻转整个字符串所有字符,"the sky is blue" -> "eulb si yks eht"
 _reverseStr(&chars,0,chars.count-1)
 
 //然后翻转每个单词中的字符，"eulb si yks eht" -> "blue is sky the"
 var startIndex = 0
 for endIndex in 0 ..< chars.count {
  if endIndex == chars.count - 1 || chars[endIndex + 1] == " " {
   _reverseStr(&chars, startIndex, endIndex)
   startIndex = endIndex + 2
  }
 }
 
 return String(chars)
}

完整算法代码：

//翻转指定范围的字符
func _reverseStr( _ chars:inout [Character], _ startIndex:Int, _ endIndex:Int){
 
 var startIndex = startIndex
 var endIndex = endIndex
 
 if startIndex <= endIndex {
  
  let tempChar = chars[endIndex]
  chars[endIndex] = chars[startIndex]
  chars[startIndex] = tempChar
  
  startIndex += 1
  endIndex -= 1
  
  _reverseStr(&chars,startIndex,endIndex)
  
 }
 
}
 
//逐字翻转字符串
func reverseWords(_ str:String) -> String{
 
 var chars = [Character](str.characters)
 
 //首先翻转整个字符串所有字符,"the sky is blue" -> "eulb si yks eht"
 _reverseStr(&chars,0,chars.count-1)
 
 //然后翻转每个单词中的字符，"eulb si yks eht" -> "blue is sky the"
 var startIndex = 0
 for endIndex in 0 ..< chars.count {
  if endIndex == chars.count - 1 || chars[endIndex + 1] == " " {
   _reverseStr(&chars, startIndex, endIndex)
   startIndex = endIndex + 2
  }
 }
 
 return String(chars)
}
 
reverseWords("the sky is blue") //return "blue is sky the"

总结

以上就是关于Swift算法实现逐字翻转字符串的方法，希望本文的内容对大家的学习或者工作能带来一定的帮助，如果有疑问大家可以留言交流，谢谢大家对小牛知识库的支持。